二、程序阅读题（每个小题单独作答，共40分）

程序阅读（2）：最小二乘法

程序拟合直线 y=ax+b。

#include <bits/stdc++.h>
using namespace std;
int NUM_SAMPLES;
void least_squares(double x[], double y[], double& a, double& b) {
    double sum_x = 0, sum_y = 0, sum_xy = 0, sum_x_squared = 0;
    for (int i = 1; i <= NUM_SAMPLES; i++) {
        sum_x += x[i];
        sum_y += y[i];
        sum_xy += x[i] * y[i];
        sum_x_squared += x[i] * x[i];
    }
    double denominator = NUM_SAMPLES * sum_x_squared - sum_x * sum_x;
    a = (NUM_SAMPLES * sum_xy - sum_x * sum_y) / denominator;
    b = (sum_x_squared * sum_y - sum_x * sum_xy) / denominator;
}
int main() {
    double x[105], y[105], a, b;
    scanf("%d", &NUM_SAMPLES);
    for(int i = 1; i <= NUM_SAMPLES; i++)
        scanf("%lf %lf", &x[i], &y[i]);
    least_squares(x, y, a, b);
    printf("a = %.1lf, b = %.1lf\n", a, b);
    return 0;
}

程序第4行参数中的 & 是取地址运算符。（ ）

{{ select(1) }}

• 正确
• 错误